Weather.Determain the temperature change in each of the following cases.?

A) 200g of water gains 8 400 j of heat.


B)15kg of water loses 252kj of heat.Weather.Determain the temperature change in each of the following cases.?
A) 10.03 degrees celsius


B) -4.01 degrees celsius





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Now, let's walk through the solutions


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First, a conversion factor:


1 calorie = 4.1868 joules





Second, a rule written into an equation


1 gram of water needs 1 calorie to raise its temperature by 1 degree celsius... which can be written in an equation format as:





1 degree celsius / gram of water = 1 calorie





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Therefore,


8400 joules = 8400/4.1868 calories = 2006.3 calories





x degrees celcius / 200 gram = 2006.3 calories





x = 10.03 degrees





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-252 kilojoules = -252,000 joules = -252,000 / 4.1868 calories = -60189.2 calories





x degrees celcius / 15,000 grams = - 60189.2 calories





x = -4.01 degrees celciusWeather.Determain the temperature change in each of the following cases.?
(14 degrees -Celsius): 1 gr of water needs 1 calorie=..4.184 J=4,2 J to raise its temperature by 1 degree, 200 gr of water need 200 calories=200 * 4.184 J=200 * 4200 J.


A)8400J/200g=42 J=10 calories, then 10 degrees. ETC